x^2+2x+1=12,16

Solution for x^2+2x+1=12,16 equation:

x^2+2x+1=12.16

We move all terms to the left:

x^2+2x+1-(12.16)=0

We add all the numbers together, and all the variables

x^2+2x-11.16=0

a = 1; b = 2; c = -11.16;
Δ = b2-4ac
Δ = 22-4·1·(-11.16)
Δ = 48.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{48.64}}{2*1}=\frac{-2-\sqrt{48.64}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{48.64}}{2*1}=\frac{-2+\sqrt{48.64}}{2}
$